Uji Minda

Posted on March 29, 2009 | 5 Comments

Diberi a = b
a^2 = ab
a^2 – b^2 = ab – b^2
(a+b)(a-b) = b(a-b)
(a+b) = b
(a+a) = a, sebab a = b
2a = a
2 = 1 !!! Kenapa? Sila jelaskan.

** a^2 bermakna ‘a kuasa 2′

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Vanessa | April 2, 2009 at 22:51 | Reply

Just giving a try..hehehe =)

Given a=b,
a^2=ab

a^2-b^2=ab-b^2
(a+b)(a-b)=b(a-b), because (a+b)(a-b)=a^2-b^2
a^2-b^2=ab-b^2
a^2-b^2=b(a-b)

then,
(a+b)=b, because (a+b)(a-b)=b(a-b)
can ‘cancel’ the (a-b)on both sides

a+b=b
since a=b,
a+a=a
2a=a
2=1 since a divide a is 1
- hussenhmhuda | April 3, 2009 at 20:29 | Reply
  
  TQ Vanessa… Can u tell me, what is the value of (a-b)? And, can we divide the equation
  (a+b)(a-b)=b(a-b) with (a-b)? Think…think…think…
  - Vanessa | April 7, 2009 at 21:45 |
    
    wahahahahaha…. yalah yalah tchr….
    
    haiyo… ya kan, what a careless mistake… consider ok la kan…. 4 months didn’t do any maths… very very rusty already…. makan, tidur, tengok tv everyday… no input at all this few months. Well, i’ll make sure i figure this question out SOMEDAY SOON!!! Look out for a reply! Hehehehehe =)
    
    (By the way, sejak bila pula cikgu2 maktab ada blog ni?! My my)
[InF]^RaZz[YaMaTeH] | April 5, 2009 at 10:11 | Reply

(a+b)(a-b) = b(a-b)
(a+b) = b <<<(a+b) is not equal to b , u can’t remove (a-b) as it is sticking wif b , b(a-b) *only the b can be “cut” , whereas (a-b) cannot *

cuz (a+b)(a-b)=b(a-b)
therefore , a^2-ab+ab-b^2=ab-b^2
a^2=ab
a(a)=ab , since a=b ,
a(a)=a(a) ~!

(a-b),
since a = b ,
(a-b) = a-a
a-a = 0
[InF]^RaZz[YaMaTeH] | April 8, 2009 at 22:26 | Reply

if u divide by (a-b) which is 0 … u get INFINITY ~!!$# [InF] =]